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−Λ∂SΛ[φ]∂Λ=∫pΛ∂ln(√ZΛKΛ(p))∂Λφ(p)δSΛ[φ]δφ(p) +∫pΛ∂∂ΛlnZΛKΛ(p)2kΛ(p)⋅kΛ(p)p212{δSΛ[φ]δφ(p)δSΛ[φ]δφ(−p)+δ2SΛ[φ]δφ(p)δ ...

webmail for student 360 staff.jpg. Quicklinks. Facebook; Linkedin; Twitter; Weibo; Mail. Back to pageTop. Want the latest Lingnan news delivered directly to your ...

For the ψ = −V2ln r potential, k is close to 4/3 for most eccentricities but ... Since Sr=∫rrp[˙r]dr=∫rrp√2ε+2ψ−h2/r2dr⁠, we see that ∂Sr(ε,h ...

e-mail: [email protected] Web site: http ... cannot connect these parameters with the structure of elementary particles, because ... ∂ξ0,i. ∂J. ∂ξ0,k −. e. c. Ak. ∂J. ∂ξ0,k } d4x,. (3.3). K = √1 + λ2 (κlκl + ∂lκl),. λ = h. mc. ,. (3.4) ... Linvectors u ∈ Ln are abstract quantities, whose properties are defined by a system. of axioms.

L∂+ ln(2 √x)] I0(√x) = K0(√x) (10). where I0and K0are, respectively, the 0-th order modified Bessel function and Macdonald function. Just as a final example ...

е-mail: [email protected] ... e-mail: [email protected] ... b))/∂T0, приведем “универсальную зависимость” к виду θs =1+(r/k) ln(V ). ... k. +. 1 ω)(. 1. 2+ √. 1. 4+ ω) =1+ r − 1 k. + ν k. 1. 1 + χω. , которое без учета переменности ...

ae-mail: [email protected] 2.1 Experimental view ... kinematic range set by the incoming hadrons can connect any of the other lines, ... The evolution equations are. ∂ ln ˜ff/H(x, bT; ζ; μ). ∂ ln. √ ζ. = ˜K(bT; μ),. (2) d ˜K d ln μ. = −γK(αs(μ)) ,. (3).

πæℏ22e2[coth(|k|Wg)+1](k∕|k|)=∫d2 p(ω−kvFpx∕p)[−∂(fe0+fh0)∂px]. ... (ω∕kvF)√(ω∕kvF)2−1=1+(æℏ2v2F4e2WgkBT)|k|Wg[coth(|k|Wg)+1]ln[2+exp(εF ...

(ω−kyvy−kzvz)δfα+ivx∂δfα∂x−iΩα∂δfα∂ϕ=−ieα{E+1c[v ... ε0zz=ω2pek2zv2Te{(1+i√π2ωkzvTe)(1−k⊥v2TeωΩe∂ ln Ne∂x)+ ...

Let us also define the photobleaching (or photodarkening) constant k 0 [cm2 mJ-1]. These constants ... (13)∂ ln T1(z, t)∂t≈k1√T2(z, t)[1-T1(z, t)]. By integrating ...